SPF(SP) Series Numerical-Locked Balance Valve

The explanation of the following diagrams

According to the formula: Kv=Q/ , Q-m 3 /h, △P-100kpa (1kgf/cm 2 ).

Example 1 : When the flow Q and △P are known, that is Q=20m 3 /h, △P=30kpa, the diameter and the opening can be obtained by following tthis procedure:

Obtain the numerical values on Q-axis and △P-aixs and draw a line between the two numerical values, then the point of intersection between the line and Kv-axis can be obtained. Draw a horizontal line which starts from the point of intersection. The the horizontal line will intersect with the valve opening scales of DN50, DN65, DN80, then the valve opening obtained are 74%, 46%, 20%, that means the balance valve can select any one from among the above-mentioned three diameters (See Diagram 1).

Example 2 : when the flow Q and diameter and the valve opening are known, that is Q=25 m 3 /h, DN65, the valve opening is 90%, the pressure differential △P can be obtained as follows:

Draw a horizontal line which starts from the point of 90% opening of DN65. The point of intersection between the horizontal line and K v-axis can be obtained. Draw a line between the point of intersection and the point of 25 m 3 /h on Q-axis and extend the line to △P-axis, then △P=8.0kpa can be easily figured out (See Diagram 2).

Example 3 : when △P, diameter and the valve opening are known, that is △P=35kpa, DN32, the valve opening 80%, the flow can be obtained as follows:

Draw a horizontal line which starts from the point of 80% opening of DN32. The point of intersection between the horizontal line and K v-axis can be obtained. Draw a line between the point of intersection and the point of 35kpa on △P-axis and extend to Q-axis, the flow rate= 7.4 m 3 /h can be obtained (See Diagram 3).

Performance Feature
SPF15-10/16
SPF45-16
Linear conversion diagram

Multifunctional Valve